college algebra

Question

Passing through (5,-8) and perpendicular to the line whose equation is y=(1)/(2)x+2

Answer 1

y = 1/2x + 1 is a rectangular hyperbola, with 2 separate branches

has slope =y'=-1/2x^2

a perpendicular line has slope = 2x^2

through the point (5,-8) the line has slope = (y+8)/(x-5) =2x^2 =2(5)^2 = 50

the line is y+8 = 50(x-5) =50x -250 y =50x-258 is the line perpendicular to the right upward branch of the hyperbola through (5,-8)

this assumes you meant y=(1/2x)+1 and not y=1/(2x+1), although the method of solving is the same

My best guess/estimate for the other perpendicular line to the other southeast branch is y=-8.125 again assuming you meant y = (1/2x)+1 Just a rough gu(es(s)timate)