need help solving

Question

What are the solutions of the quadratic equation?

4x²−9x−9=0

Answer 1

An equation in the form: ax²+bx+c=0

the quadratic equation will be used.

X₁=(-b+radical(b²-4ac))/(2a)

X₂=(-b-radical(b²-4ac))/(2a)

Therefore:

X₁=(-(-9)+radical((-9)²-4(4)(-9)))/(2(4))=(9+15)/8=3

X₂=(-(-9)-radical((-9)²-4(4)(-9)))/(2(4))=(9-15)/8=-3/4

X₁=3 and X₂=-3/4

Answer 2

The easiest way for this one is to use the quadratic formula, but it also factors

as (x-3)(4x+3).

Answer 3