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Jordan B.

asked • 01/26/22

Pre-Calculus Logs

Solve log_b(2b)^-2given: log_b 2 = 0.3562

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Raymond B. answered • 04/15/22

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log(2b) = -2log(2b)

= 2log2 + 2logb

= 2log2 + 2(1)

= 2log2 + 2

=2(.3562) +2 = 2.7124

b=7

log₇(2(7))^-2 =log₇(1/196) = -2,7124

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