Find three consecutive odd numbers such that the sum of five times the smaller number and twice the larger number is 33 more than six times the median number.

Question

I am trying to find 3 positive executive positive integers it's for my algebra 2 class

Answer 1

5S + 2L - 33 = 6M

S = M-2

L = M+2e

5(M-2) + 2(M+2) - 33 = 6M

5M + 2M -6M = 33 -4 +10 = 39

M = 39 = the middle odd integer

S = 37 = smallest odd integer

L = 41 = largest odd integer

check the answer

5(37) + 2(41) - 33 = 6(39)

185 + 82 -33 = 234

267-33 = 234

Answer 2

Hi Jacklyn G.

Let x = smallest odd number

Let x + 2 = middle odd number

Let x + 4 = largest odd number

5x + 2(x + 4) = 33 + 6(x + 2)

Follow PEMDAS then solve for x

I hope this helps if you have any questions or need help proceeding just send me a message