The length of a rectangle is eight more than double the width. If the perimeter is 88 inches, find the dimensions.

Answer 1

L = 8 + 2W

88 = 2(L+W)

44 = L+W = 8+2W + W = 8 + 3W

3W = 44 -8 = 36

W = 36/3 = 12 inches wide

L = 8 + 2(12) = 8 + 24= 32 inches long

Perimeter = 2(L+W) = 2(32 + 12) = 2(44) = 88 inches