(2/x)+6 / (1/y)

Question

I really don't understand, I got (2y/x+6y) but just want to make sure

Answer 1

OK, I think the problem is ((2/x) + 6) / (1/y):

((2/x) + 6) / (1/y)

When you divide by a fraction, it's the same as multiplying by the reciprocal of the fraction. The reciprocal of 1/y is y/1 or just y. So:

(2/x + 6) / (1/y) = (2/x + 6) · y = 2y/x + 6y

which is what you got. If you want to put it over a common denominator, multiply the 6y by x/x and you get:

2y/x + 6y·(x/x) = (2y + 6xy)/x = 2y(1+3x)/x