A chemist has one solution containing 20% acid, and a second containing 30% acid. How many liters of each solution must be combined to obtain 80 liters of a mixture that is 28% acid?

Answer 1

Do a volume balance and an acid balance, then solve for Vol of 20% acid. Let V be this value:

V of the 30% acid = 80-V

0.2V + 0.3(80 - V) = 0.28*80 Solve this for V