solve for theta, to the nearest degree, in the interval 0 to 180

Question

5 tan² theta + 3 tan theta = 2

Answer 1

5tan²θ +3tanθ - 2 = 0

(5tanθ - 2)(tanθ + 1) = 0

 

tanθ = 0.40 ⇒21.80°

 

or

 

tanθ = -1 ⇒ 135°