Michael J. answered 03/15/15
Tutor
5
(5)
Effective High School STEM Tutor & CUNY Math Peer Leader
First get rid of the square-root by raising both sides of equation to the 2nd power.
(x2 + 5)2 = 7x - 2
x4 + 10x2 = 7x - 2
Next, make one side equal to zero.
x4 + 10x2 - 7x + 2 = 0
We have a polynomial whose degree is 4 because the first term is x4. The term after that is x2. These two terms graph the same way, so we will take x2 as the first term, making the polynomial of degree 2.
If the formula used to find the roots of the quadratic equation is (-b ± √(b2 - 4ac)) / 2a,
where:
a = 10
b = -7
c = 2
then the discriminant is the square-root part in the formula: √(b2 - 4ac).
If b2 < 4ac, then the value under the square-root is negative and will be imaginary.
If b2 ≥ 4ac, then the value under the square-root is positive and will be real.
Let's find b2 and 4ac using the parameters above.
b2 = (-7)2 = 49
4ac = 4(10)(2) = 80
49 < 80. Therefore, you will have two complex solutions since the formula has ±.
Your answer is (b).