Raymond B. answered 01/18/22
Math, microeconomics or criminal justice
If 78% decays, that leaves 100-78 = 22% left
half life = 30 seconds
A = Pe^-30r
.5 = e^-30r
take logs
ln(.5) = -30r
r = ln(.5)/-30 = .0231
.22 = e^-t(.0231)
take natural logs of both sides
ln.22 = -.0231t
t = ln.22/-.0231 = 65.5467 seconds to decay 78% of the sample
if the half-life is 30 seconds
75% will decay in 60 days, "1/4 or 25% life"
22% takes a little longer than 25%, so a little more than 60 seconds is required. 65.5446 is a little more than 60 seconds.