Raymond B. answered 01/18/22
Math, microeconomics or criminal justice
x-y+z = 0
y +2z = -2
x+y-z = 2
add the 1st and last equations to eliminate y and z, leaving
2x = 2,
divide by 2
x=2/2 = 1
x= 1
plug that into the 1st equation: 1-y+z = 0,
y=z+1
plug that into the 2nd equation
y+2z = -2
z+1 +2z = -2
3z = -3
z = -1
y= z + 1 = -1 + 1 = 0
y =0
(x,y,z) = (1,0, -1)
check that with the 3rd equation:
x +y -z = 2
1 +0 -(-1) = 2
2= 2
solution is x= 1, y= 0, z=-1