If S is the amt of 12% and L the amt of 30%, then the equations are
S + L = 90
.12S + .3L = .22*90
You can use either elimination or substitution to find the solution.
Jonelle S.
asked 11/23/21How many liters each of 12% iodine solution and a 30% iodine solution must be used to produce a total mixture of 90 liters of a 22% iodine solution?
If S is the amt of 12% and L the amt of 30%, then the equations are
S + L = 90
.12S + .3L = .22*90
You can use either elimination or substitution to find the solution.
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