Find a polynomial f(x) of degree 3that has the following zeros. 0,9,-1

Answer 1

Hello Christine,

Polynomials are generally in the form P(x) = a* (x- zero₁) (x - zero₂) ( x- zero₃) .....(x-zero_n) where n is indicative of the degree of the polynomial

Here you have a degree 3 polynomial, so 3 zeros:

f(x) = a* (x-0) (x-9)(x+1) = a*x(x-9)(x+1)

You weren't given any additional details, so a can be any real number that's non-zero.

If you choose a = 1, then f(x) = x*(x-9)*(x+1) is an answer