(3x3) / (3x - 6)
= (3x3) / 3(x - 2)
= x3 / (x - 2)
= x3 / - (2 - x)
= - x3 / (2 - x)
= - x3·(x2 + 9)/ (2 - x)·(x2 + 9)
= (- x5 - 9x3) / (2 - x)·(x2 + 9)
Princess S.
asked 11/07/21Write an expression equivalent to (3x3) / (3x-6) with a denominator of (2-x)(x2+9).
(3x3) / (3x - 6)
= (3x3) / 3(x - 2)
= x3 / (x - 2)
= x3 / - (2 - x)
= - x3 / (2 - x)
= - x3·(x2 + 9)/ (2 - x)·(x2 + 9)
= (- x5 - 9x3) / (2 - x)·(x2 + 9)
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Princess S.
Ah thank you so much I think I finally understand this problem ^-^11/08/21