Raymond B. answered 02/01/23
Tutor
5
(2)
Math, microeconomics or criminal justice
f(x) =ax(x-2)^2
f(3) =12 = a(3)(3-2)^2 = 3a
a =12/3 = 4
f(x)= 4x(x-2)^2
= 4x(x^2-4x +4)
= 4x^3 -16x^2 +16x
John S.
asked 10/30/21Find a polynomial function f(x) of degree 3 with real coefficients that satisfies the following conditions.
zero of 0 and zero of 2 having multiplicity 2; f(3)=12
Raymond B. answered 02/01/23
Math, microeconomics or criminal justice
f(x) =ax(x-2)^2
f(3) =12 = a(3)(3-2)^2 = 3a
a =12/3 = 4
f(x)= 4x(x-2)^2
= 4x(x^2-4x +4)
= 4x^3 -16x^2 +16x
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