(rx^3+5x^2)/x-5

Question

how would you do long division of polynomials with two different variables in the dividend and one in the divisor?

What do you do with the r term?

Answer 1

Just treat it like any other coefficient.

rx²+5(r+1)x+25(r+1) + 125(r+1)/(x-5)

+-----------------------------

x-5 |rx³+5x²

rx³-r5x²

-----------

5(r+1)x²

5(r+1)x² -25(r+1)x

------------------------

25(r+1)x

25(r+1)x -125(r+1)

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125(r+1) <--- remainder