How can I graph this? {Parabolas} y=2x^{2}+3x-3

Question

I never learned how to graph standard form only vertex.

Answer 1

y = 2x² + 3x - 3

To graph it, you can start by plugging in x values to find y-values.

For example if x = 1, y = 2(1)² + 3(1) - 3, y = 2 (1, 2)

if x = 0, y = -3

if x = -1, y = -4

Find the vertex of the parabola with -b/2a.

If y = ax2 + bx + c.....a = 2 b = 3 c = -3

Vertex is -3/2(2) = -3/4

y = 2(-3/4)² + 3(-3/4) - 3 = -33/8

Vertex coordinate is (-3/4, -33/8)

You could also use the Quadratic Formula to find the x-intercepts: x = −b ± √(b2 − 4ac) / 2a

The easiest way is to just plug in x-values to find the y-values.