write an equation of parabola in intercept form

Question

passes through (14,4) with c-intercepts of 12 and -6

Answer 1

ASSUMPTION:

c-intercepts are x-intercepts

The intercept-form of a parabola is simply the factored-form

y = a(x - b)(x - c)

Plug all the provided values in, then solve for the coefficient a:

4 = a(14 - 12) (14 - -6)

4 = a(2)(20)

4 = 40a

a = 1/10

Therefore, an equation of a parabola in intercept-form that passes through the point (14,4) and has x-intercepts of 12 and -6 is

y = 1 (x - 12)(x + 6)

10