Using this equation, find out the time at which the rocket will reach its max, to the nearest 100th of a second. y=-16x^2+190x+72

Question

A rocket is launched from a tower. The height of the rocket, y in feet, is related to the time after launch, x in seconds, by the given equation.

Answer 1

y = -16(x - 95/16)² + 10177/16.

And we have max if x = 95/16 = 5.94 sec