This is a common question type for Algebra 1 that can be solved by setting up a system of linear equations. The question guides you to see that we have two unknowns: the # of each type of coin. We will be able to set up one equation using the total number of coins, and set up a second equation by using the total value:
Let d: # of dimes ; q: # of quarters
d + q = 22
10d + 25q = 370 Multiply 1st equation by - 10. Then add the 2 eqns, left side to left side, right to right:
-10d - 10q = - 220 (This technique is known as elimination. Substitution would also work well here.)
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15q = 150
q = 10 ; d = 12