Raymond B. answered 10/09/21
Math, microeconomics or criminal justice
log((x^4)(y^5)(sqr(z)))
= log(x^4) + log(y^5) = log(sqr(z))
= 4log(x) + 5log(y) = (1/2)log(z)
A=4, B=y
C=5, D=y
E=-1/2, F = z
UNLESS, the problem was intended to be
log((x^4)(y^5)/z) That seems likely as -ElogF is used rather than +ElogF
IF that's the problem then
log((x^4)(y^5)/z) = 4logx + 5logy -logz
with E=1 instead of -1/2
A still = 4, B=y, C=5, D=y, F=z