C(4,2)C(2,1)C(6,0) = 6*2*1 = 12

Not asked, but the probability of this selection would be

12/C(12,3) = 12/220 = 3/55

Camelia A.

asked • 10/02/21A bag contains 4 black, 2 red, and 6 yellow blocks. A sample of 3 is selected. How many samples are possible in which the blocks are 2 black and 1 red?

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C(4,2)C(2,1)C(6,0) = 6*2*1 = 12

Not asked, but the probability of this selection would be

12/C(12,3) = 12/220 = 3/55

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