Raymond B. answered 10/02/21
Math, microeconomics or criminal justice
A is 9 miles away, going 1/3 mile per minute
N is 3 miles away walking 1/17 mile per minute
they are 6 miles apart
T/3 = 6 + T/17
multiply by 3(17)
17T = 6(3)(17) + 3T
14T = 306 = 306/14 = 153/7 minutes
T= about 21.86 minutes or 21 minutes and 51.4 seconds
1/3(153/7) = 153/21 = about 7.29 miles
they're both 9-7.29 = 1.71 miles from the stadium when they meet