Raymond B. answered 07/17/25
Tutor
5
(2)
Math, microeconomics or criminal justice
roots -1, 1/2 1-i, 1+i, imaginary roots come in conjugate pairs
2(x+1)(x-1/2)(x-1+i)(x-1-i)
expand
(x+1)(2x-1)(x^2 -(1-i)(1+I))
= (2x^2 +x-1)(x^2 -2x+2)
= 2x^4 -4x^3 +4x^2 +x^3 -2x^2 +2x -x^2 +2x-2
= 2x^4-3x^3 +x^2 +4x -2