How many grams of calcium nitrate needs to be added to make 400 mL of solution that has a molarity of 2.5?

Question

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Answer 1

Mass of 1mole of calcium nitrate = molar mass of Ca + molar mass of N + 3 * molar mass of O

                                                = 40g + 14g + 3*16g = 102g

 

n(CaNO₃) in 400ml 0f 2.5 molar solution = .4litre * 2.5 mol/litre = 1 mol

 

Grams of CaNO₃ = mass of 1mol of CaNO₃ = 102gm