Suppose that x is the length and y the width. Then we have the equations 2x+2y=60 and x=2y. We obtain that 4y+2y=60 or 6y=60 or y=10 and x=20.
Lydia S.
asked 09/17/21A rectangle is twice as long as it is wide. The perimeter is 60 feet. Find the dimensions
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