The Characteristic Equation being λ2 +λ -2 = 0,
the eigenvalues are λ = 1 and λ = -2
and the corresponding eigenvectors x1 = < 1,1> and x2 = < 1, -2 >
The general solution
x(t) = c1 et +c2 e-2t
y(t) = c1 et -2c2 e-2t
Adrian A.
asked 09/16/21The Characteristic Equation being λ2 +λ -2 = 0,
the eigenvalues are λ = 1 and λ = -2
and the corresponding eigenvectors x1 = < 1,1> and x2 = < 1, -2 >
The general solution
x(t) = c1 et +c2 e-2t
y(t) = c1 et -2c2 e-2t
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