perimeter, area, square yards

Question

a rectangular field has a perimeter of 200 yd and an area of 2500 square yards. find it’s dimensions. select all statements that are true.

Answer 1

We seem to be missing your options here, but here is what we know:

Perimeter = 2*L + 2*W = 200 yd

Area = L*W = 2500 yd²

Solve for a variable, L in this case:

(Perimeter Equation) L = 100 - W

(Plug into Area Equation)..

(100 - W) * W = 2500

W²-100*W+2500 = 0

(W-50)² = 0 so W = 50, and L = 50.

Answer 2

x + y = 100

xy = 2500

y = 100 / x

x + (100 / x) = 2500

x² + 100 = 2500x

x² - 2500x + 100 = 0

The solution is irrational. Are the numbers accurate?