The ages of three friends are consecutive integers. If the sum of the three friends 'age is 45,which equation below can be used to determine the age of the youngest friend ?

Question

A. 3x=4

B. 3×+6=45

C.3×3=45

D. 3×+3=45

2. Solve the equation 8-8m=8m+56

Answer 1

We know the youngest have to be x, but then since all their ages are consecutive, then their ages should be going up by 1. Hence,

Youngest Friend = X

Second Friend = X + 1

Last Friend = X + 2

Since we know their sum has to be 45, we can then set up the equation as

X + (X + 1) + (X + 2) = 45

or simply

3X + 3 = 45 (D)

Answer 2

Hello, Christabel

1. Set x = the youngest friend. Then the other two must be x+1 and x+2, since they are consecutive integers. Theuiir sum is 45:

x + x+1 + x + 2 = 45

3x + 3 = 45

That looks like the equation in D, and it makes sense. [FYI, the youngest, x, is 14.

14+15+16 = 45]

2. Solve the equation 8-8m=8m+56

8-8m = 8m+56

8 - 56 = 8m + 8m

-48 = 16m

16m = -48

m = -3

Bob