Patrick F. answered • 08/30/21
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P(at least 1 green ball) = 1 - P(zero green balls) = P(red from A) * P(red from B) = 5/7 * 3/7
Kevin L.
asked • 08/30/21Algebra II Question
Two boxes contain balls of various colors. Box A contains 5 red balls and 2 green balls, and Box B contains 3 red balls and 4 green balls. One ball is randomly drawn from each box. What is the probability that at least one green ball is chosen?
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