Hi Plz Help me It's Piecewise function

Question

f(x)= x+5 x<-2

x²+2x+3 x≥2

Function? Yes or No

f(3)=

f(-4)=

f(-2)=

f(-1)=

f(0)=

2.f(x)= 2x+1 x≥ 1

x²+3 x<1

Function? Yes or No

f(-2)=

f(3)=

f(1)=

f(-1)=

PLZ Help Me It's Piecewise Function

Answer 1

Hi,

f(x)= x+5 x<-2

x²+2x+3 x≥2

Be care full domain is <=========-4====-2------1----0--------2===3=============>

Function? Yes or No---> yes, it is function. by graphing you see the definition of function. in other word, there is not any common number between x<-2 and x>2

f(3)= (3)^2 + 2(3) + 3 = 9 + 6 + 3 = 18

you need to recognize 3 belongs to domain of which part of function then replace 3 instead of x

f(-4)=-4 + 5 = 1

f(-2)= undefined because for x=-2 is not in t the domain of function

f(-1)=undefined because for x=-1 is not in t the domain of function

f(0)=undefined because for x=0 is not in t the domain of function

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2.f(x)= 2x+1 x≥ 1

x²+3 x<1

it is very similar to the previous question

Function? Yes or No--->yes, it is function. by graphing you see the definition of function. in other word, there is not any common number between x<1 and x>=1

f(-2)= (-2)^2 +3 = 7

f(3)= 2(3) + 1 = 7

f(1)= 2(1) +1 = 3

f(-1)= (-1)^2 +3 =4

I hope it is useful,

Minoo