Write an equation for a line perpendicular to y = − 3 x + 3 and passing through the point (3,-2)

Answer 1

perpendicular line has a negative inverse slope: take -3, change the sign and flip it upside down: 1/3

y=(1/3)x + b solve for b by plugging in the point

-2 = (1/3)3 + b = 1+b

b =-2-1 =-3

b =-3

y = x/3 -3 is the perpendicular line through the given point