
Thomas H. answered 08/25/21
Different Approaches! Fill in the Gaps!
One Line [A} is perpendicular to a Second Line [B] if it has a slope that is the "NEGATIVE RECIPROCAL" of the first one.
A negative reciprocal is the fraction you multiply the first fraction to get -1.
Basically, flip the fraction and change its sign (the negative reciprocal of 2/3 is -3/2)
So its a 2 step process:
Find the original slope.
The find the y-intercept (the place on the y axis where x is 0).
So,
slope is rise (difference in Y-coordinates) over run (difference in X-coordinates)
7 - 0 = 7 That's the original slope
-5 - 4 -9
The slope of the perpendicular line (flip and change sign) is 9
7
now you need a line that has that new slope where one answer is
(4,0)
to do this you can use the "POINT-SLOPE" formula
(Y - Yp) = m(X - Xp)
Y and X are just variables
Yp and Xp are the x and y for point P(4, 0)
m is the SLOPE
now just plug and play
(Y - 0) = 9 (X-4)
7
Y= 9X - 4
7 7
subtract the Y to move it on the same side as the rest of the equation...
9X - Y - 4 = 0
7 7
Now make integers out of everything, multiply everything by 7.
If you multiply everything in an equation by the same number, the equation is still true.
9x - 7y - 4 = 0
David W.
NOTICE: "where a,b,c are integers" ... 9x - 7y - 36 = 008/24/21