Can someone please answer this problem

Question

A sealed container holding 0.0255 L of an ideal gas at 0.995 atm and 69 ∘C is placed into a refrigerator and cooled to 45 ∘C with no change in volume. Calculate the final pressure of the gas. 𝑃= atm

Answer 1

Consider the Combined Gas Law: P1V1/T1 = P2V2/T2 and since volume (V1 and V2) is constant, we can eliminate it from the equation. We are left with P1/T1 = P2/T2

P1 = initial pressure = 0.995 atm

T1 = initial temperature = 69ºC + 273 = 342K (NOTE: temperature is always in Kelvin)

P2 = final pressure = ?

T2 = final temperature = 45ºC + 273 = 318K

Plug in values and solve for P2:

0.995 atm / 342K = P2 / 318K

P2 = (0.995 atm)(318K) / 342K

P2 = 0.925 atm