Can someone please complete this

Question

A sample of an ideal gas has a volume of 3.80 L at 14.80 ∘C and 1.50 atm. What is the volume of the gas at 19.00 ∘C and 0.996 atm? 𝑉= L

Answer 1

Combined Gas Law: P1V1/T1 = P2V2/T2

Plug in the values and solve for V2 (final volume)

(1.50 atm)(3.80 L) / 287.8K = (0.996 atm)(V2) / 292K (NOTE: temps are in Kelvin)

V2 = 5.81 L