USING THE WASHER METHOD
V = π∫-12 [ex]2 dx =(π/2) [ e2x] |-12= (π/2) ( e4-e-2)
USING THE SHELL METHOD
V = ∫e^-1e^2[ 2πy( 2-lny)] dy + ∫e^-10 2πy( 2-(-1)) dy =
∫e^-1e^2[ 4π] ydy - ∫e^-1e^2[ 2πylny] dy + ∫e^-10 6πy dy =
2πe4 -2πe-2 - π ∫e^-1e^2lnyd y2 + 3πe-2 =
2πe4 -2πe-2 - [πy2lny] |e^-1e^2 + π ∫e^-1e^2 y2 (1/y) d y +3πe-2 =
2πe4 -2πe-2 -πe4lne2 + πe-2lne-1+ π ∫e^-1e^2 y d y +3πe-2
π/2 [ e4-e-2]