USIND THE CYLINDRICAL SHELL METHOD
V= ∫12 2πx [ 0 - ( x2-3x +2)]dx = π / 2
USING THE WASHER METHOD
In this case you need the outer and the inner radius of revolution
by solving the equation x2 - 3x +2 -y =0 for x
XOUTER = 3/2 + 1/2√(1+4x)
XINNER = 3/2 - 1/2√(1+4x)
Then V= ∫-1/40 π [ {3/2 + 1/2√(1+4x)}2 - {3/2 - 1/2√(1+4x)}2 }dy = π/2