This is a regular question and is doesn't have a lab with it. Can I please get some help?

Question

Combining 0.255 mol Fe2O3 with excess carbon produced 14.8 g Fe.

Fe2O3+3C⟶2Fe+3CO

What is the actual yield of iron in moles?

Answer 1

Let's look at the balanced equation for the reaction taking place:

Fe₂O₃ + 3C ==> 2Fe + 3CO

From the stoichiometry, we see that 1 mol Fe2O3 produces 2 mols Fe

0.255 mol Fe₂O₃ x 2 mol Fe / 1 mol Fe₂O₃ = 0.510 mols Fe formed THEORETICAL YIELD

Converting this to grams, we have...

0.510 mols Fe x 55.85 g /mol = 28.48 g of Fe ... THEORTETICAL YIELD

% yield = actual yield / theoretical yield (x100%) = 14.8 g / 28.5 g (x100) = 51.9% yield