Can someone please answer this question

Question

A student performed an experiment of heating a hydrate and obtained the following data. The mass of an empty crucible was 17.556g. The mass of crucible and a hydrate was 21.018 g. The mass of crucible and anhydrous salt (after heating) was 19.641g. Answer the followings:

a. Calculate the mass of the hydrated salt

.b. Calculate the mass of water lost due to heating.

c. Calculate the percent water in the hydrate

Answer 1

This question in involves a hydrate of an unknown compound.

Given:

1) mass of empty crucible - 17.556 g

2) mass of crucible and hydrate - 21.018 g

3) mass of anhydrous salt after heating - 19.641 g

Find:

a) mass of hydrated salt

hydrated salt in the crucible - empty crucible = hydrated salt alone in g

21.018 g - 17.556 g = 3.462 g

b) calculate mass of H2O lost after heating the hydrate

mass of hydrate ( with crucible) - mass of anhydrous salt remaining in crucible

21.018 g - 19.641 g = 1.377 g ( the crucible is a constant since these weights involves the crucible)

the mass of water lost from the hydrate = the mass of water that was in the hydrate

c) calculate the % of H2O in the hydrate

The water lost from the hydrate = the water that was in the hydrate originally

mass of water in the hydrate (water lost from the hydrate)/mass of the hydrated salt x 100

1.377 g/3.462 g = 0.3977 x 100 = 39.77 %