A rectangular run is built on the side of a garage using 50 ft fencing. One side of the run is one of the walls of the garage. a)What dimensions maximize the area? b)Maximum area? c)Draw diagram

Question

Please answer my question and show me how you got it as soon as you can.

Answer 1

2W + L = 50

L=50-2W

Area = A = LW = (50-2W)W = 50W -2W^2 take the derivative and set it equal to zero

A' = 50 - 4W = 0

4W =50

W -50/4 = 12.5 feet wide

L= 25 feet long parallel to the garage

Maximum area = 12.5(25) = 312.5 ft^2

12 1/2 by 25 feet maximizes the area