Yefim S. answered 06/17/21
Math Tutor with Experience
f(x) = 2(x - 1)(x2 + 3)/[(x - 1)(x + 2)x].
This function has 2 vertical asymptotes x = 0 and x = - 2; 1 horizontal asymptote y = 2;
it has hole at x = 1, y = 2·4/3 = 8/3 or point (1, 8/3) is whole.
In standard form f(x) = 2(x3 - x2 + 3x - 3)/(x3 + x2 - 2x)