The first thing to do, and often the hardest, is to find some sort of relationship between the terms of the sequence.
A good way to start is the look at the 1st difference, then the second difference, 3rd difference, and so forth.
Since the 1st difference is not the same, this is NOT a linear function.
Since the 2nd difference is not the same, this is NOT a quadratic function.
Unfortunately, we don't have enough terms to take any more differences.
We can use a TI-84 calculator to test other possibilities fairly easily.
Plug the numbers into a "list" like this (using "stat" then "edit" "1:Edit"):
L1 | L2
----------|-------------
1 | 500
2 | 751
3 | 1124
4 | 1688
Then use "stat" "CALC" "6:CubicReg" to find out if this is a cubic function. You should get the following:
y=ax3+bx2+cx+d
a=11.5
b=-8
c=194.5
d=302
R2=1
An "R2" of 1 means a perfect fit so the relationship is a cubic function with those values for the coefficients.
So you could use:
14
∑ (11.5x3 - 8x2 + 194.5x + 302)
x=1
I got an answer larger than 143,000
William W.
06/08/21
Laurie C.
so would it be 14(11.5x^3 -8x^2 + 194.5x + 302) when x = 1 because I just don't see where you plug in the 14th day into the equation if it dosen't go first?06/07/21