
Bradford T. answered 06/01/21
Retired Engineer / Upper level math instructor
If you try linear
f(x)= ax+b
f(0) = 1 = b
f(1) = a+1=6 --> a= 5
f(2) = 5(2) +1 = 11 ≠ 29 No
If you try quadratic
f(x) = ax2+bx+1
f(1) = a+ b + 1 = 6 --> a+b = 5
f(2) = 4a +2b +1 = 23 --> 4a+2b = 22 --> a=2, b = 7
f(x) = 2x2+7b+1
f(3) = 18+21+1 =40 ≠ 88 No
If you try cubic
f(x) = ax3+bx2+cx+1
f(1) = a+b+c +1 = 6 --> a+b+c =5
f(2) = 8a+4b+2c+1 = 29 --> 8a+4b+2c = 28
f(3) = 81a+9b+3c+1 = 88 --> 81a+9b+3c = 87
Solving: a=3, b=0, c = 2
f(x)=3x3+2x+1
f(4)=192+8+1 = 201 Yes
f(5)=375+10+1=386 Yes
Answer D) Cubic

David C.
06/01/21