
Bradford T. answered 05/28/21
Retired Engineer / Upper level math instructor
There are 10 letters of which there are:
2-A's
2-B's
2-L's
4-single letters left
Number of arrangements = C(10,2)C(8,2)C(6,2)4! = (10!/(2!8!))(8!/(2!6!))(6!/(2!4!))4! = 10!/8 = 3628800/8 = 453600
Answer (2)