what is the sum of the first ten terms in a geometric series with a1= 2 & r= 3

Answer 1

k

S_k=∑a₁r^n-1 = a₁(1-r^k)/(1-r)

n=1

For this case:

S₁₀=2(1-3¹⁰)/(1-3) = (2/-2)(1-59049) = 59048