Answer the algebra question correctly.

Question

Quincey graphed a parabola in the coordinate grid.

Which points on the graph correspond to P (0, 4) and Q (4, 1) in Quincey's graph?

A. P'(2, 1) and Q'(5, 4)

B.P'(5, 4) and Q'(2, 1)

C.P'(1, 2) and Q'(4, 5)

D.P'(4, 5) and Q'(1, 2)

Answer 1

It's a parabola with vertex (3,0)

which is y=(x-3)^2

for (1,4) 4=(1-3)^2 = 2^2 (You probably made a typo and meant (1,4) not (0,4) the 1 and 0 are close on the keyboard and maybe you punched the wrong one)

for (4,1) 1 = (4-3)^2 = 1^2

It's the parabola y=x^2 shifted to the right 3 units

(2,1) and (5,4) are also on the parabola y=(x-3)^2

for (2,1) 1=(2-3)^2 = 1^2

for (5,4) 4=(5-3)^2 = 2^2

the points that were (1,4) and (4,1) become (2,1) and (5,4) if you increase x by one and find the corresponding y values on the parabola

A) is probably the answer you want

although usually this type of problem involves a shift in the parabola, right, left, up or down. But this is a movement along the parabola without any shift in the parabola itself.