which of the following describes the end behavior of g(x)=x^2-6/x^2-2 as x approaches negative infinity?

Question

A. y approaches -6

B. y approaches 1

C. y approaches negative infinity

D. y approaches 0

Answer 1

g(x)=x^2-6/x^2-2 as x approaches negative infinity?

Again, I'm interpreting the formula, which doesn't get copied well on this site, as (x² - 6)/(x² - 2).

As x approaches negative infinity, the -6 and -2 have no affect, so the x²'s cancel leaving = 1.