Raymond B. answered 05/20/21
Tutor
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Math, microeconomics or criminal justice
(-8,0) (8,0) as foci point (8,30) on the hyperbola
distance from (8,0) to (8,30) is 30
distance from (-8,0) to (8,30) is d = sqr(30^2+ 16^2) = sqr(900+256) = sqr(1156) = 34
34-30 = 4 = constant difference in distances to each focus from a point on the hyperbola