
Alma H.
asked 05/16/21I NEED HELP !!!! pls
In the design of Mr. Cochran's tiny house, he hopes to be completely off grid. That means he needs to generate enough power to manage electricity without connecting to city power lines. A typical solar panel can generate 15 watts of power per square foot. This means daily, a square foot of solar panel is like to store 75 watt hours of power. If his current monthly power consumption is around 60,000 watt hours, design a solar panel that is able to provide exactly enough power. Keep in mind, the tiny house is only 8.5' wide and 24' long, he plans to mount the solar panels on top of the house...
1 Expert Answer
Hi Alma H.,
Mr. Cochran's consumption of 60,000 watt*hrs. per month, is 2,000 watt*hrs. per day (60,000/30). If each square foot of solar panel provides 75 watt*hrs. per day, Mr. Cochran's tiny house needs 2,000/75 = 26.67 or 27 ft.2 of solar panels ( A 3-ft. x 9-ft. set of 1 ft.2 solar panels). Mr. Cochran's tiny house roof is 8.5 ft. * 24 ft. = 204 ft.2, so the solar panels will take up 27/204 = 13.3% of the roofs area.
I hope this helps, Joe.
Alma H.
Thank you!05/17/21
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Mark M.
With what do you need help? The information is explicit and the goal is definite.05/17/21