Identify the 31st term of an arithmetic sequence where a1 = 26 and a22 = −226. −334 −274 −284 −346\

Answer 1

a₂₂ = a₁ + 21d formula

-226 = 26 + 21d

Can you solve for d?

a₃₁ = 26 + 30d

Can you solve for a₃₁ and answer?

Answer 2

d=-12= the common difference

d = (a22-a1)/(22-1) = (-226-26)/21 = -252/21 =-12

an=a1 + (n-1)d

a31 = 26 + (31-1)(-12) = 26 +30(-12) = 26-360 = -334